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5(4x+1)=-4(3x-5)+3x
We move all terms to the left:
5(4x+1)-(-4(3x-5)+3x)=0
We multiply parentheses
20x-(-4(3x-5)+3x)+5=0
We calculate terms in parentheses: -(-4(3x-5)+3x), so:We get rid of parentheses
-4(3x-5)+3x
We add all the numbers together, and all the variables
3x-4(3x-5)
We multiply parentheses
3x-12x+20
We add all the numbers together, and all the variables
-9x+20
Back to the equation:
-(-9x+20)
20x+9x-20+5=0
We add all the numbers together, and all the variables
29x-15=0
We move all terms containing x to the left, all other terms to the right
29x=15
x=15/29
x=15/29
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