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5(4x+10)-2(x-4)=7x(x+4)-x(7x-2)
We move all terms to the left:
5(4x+10)-2(x-4)-(7x(x+4)-x(7x-2))=0
We multiply parentheses
20x-2x-(7x(x+4)-x(7x-2))+50+8=0
We calculate terms in parentheses: -(7x(x+4)-x(7x-2)), so:We add all the numbers together, and all the variables
7x(x+4)-x(7x-2)
We multiply parentheses
7x^2-7x^2+28x+2x
We add all the numbers together, and all the variables
30x
Back to the equation:
-(30x)
-12x+58=0
We move all terms containing x to the left, all other terms to the right
-12x=-58
x=-58/-12
x=4+5/6
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