5(4x+12)-36=140-6(2x-2)

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Solution for 5(4x+12)-36=140-6(2x-2) equation: 



5(4x+12)-36=140-6(2x-2)

We move all terms to the left:

5(4x+12)-36-(140-6(2x-2))=0

We multiply parentheses

20x-(140-6(2x-2))+60-36=0



We calculate terms in parentheses: -(140-6(2x-2)), so:

140-6(2x-2)

determiningTheFunctionDomain
-6(2x-2)+140

We multiply parentheses

-12x+12+140

We add all the numbers together, and all the variables

-12x+152

Back to the equation:

-(-12x+152)



We add all the numbers together, and all the variables

20x-(-12x+152)+24=0

We get rid of parentheses

20x+12x-152+24=0

We add all the numbers together, and all the variables

32x-128=0

We move all terms containing x to the left, all other terms to the right

32x=128

x=128/32

x=4

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