5(4x+3)+9x=(20x+15)+9x

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Solution for 5(4x+3)+9x=(20x+15)+9x equation: 



5(4x+3)+9x=(20x+15)+9x

We move all terms to the left:

5(4x+3)+9x-((20x+15)+9x)=0

We add all the numbers together, and all the variables

9x+5(4x+3)-((20x+15)+9x)=0

We multiply parentheses

9x+20x-((20x+15)+9x)+15=0



We calculate terms in parentheses: -((20x+15)+9x), so:

(20x+15)+9x

We add all the numbers together, and all the variables

9x+(20x+15)

We get rid of parentheses

9x+20x+15

We add all the numbers together, and all the variables

29x+15

Back to the equation:

-(29x+15)



We add all the numbers together, and all the variables

29x-(29x+15)+15=0

We get rid of parentheses

29x-29x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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