5(4x+3)-5=4(2x-2)

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Solution for 5(4x+3)-5=4(2x-2) equation: 



5(4x+3)-5=4(2x-2)

We move all terms to the left:

5(4x+3)-5-(4(2x-2))=0

We multiply parentheses

20x-(4(2x-2))+15-5=0



We calculate terms in parentheses: -(4(2x-2)), so:

4(2x-2)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

20x-(8x-8)+10=0

We get rid of parentheses

20x-8x+8+10=0

We add all the numbers together, and all the variables

12x+18=0

We move all terms containing x to the left, all other terms to the right

12x=-18

x=-18/12

x=-1+1/2

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