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5(4x+3)13x=+64
We move all terms to the left:
5(4x+3)13x-(+64)=0
We add all the numbers together, and all the variables
5(4x+3)13x-64=0
We multiply parentheses
260x^2+195x-64=0
a = 260; b = 195; c = -64;
Δ = b2-4ac
Δ = 1952-4·260·(-64)
Δ = 104585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-\sqrt{104585}}{2*260}=\frac{-195-\sqrt{104585}}{520} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+\sqrt{104585}}{2*260}=\frac{-195+\sqrt{104585}}{520} $
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