5(4x+3)=(x-2)

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Solution for 5(4x+3)=(x-2) equation: 



5(4x+3)=(x-2)

We move all terms to the left:

5(4x+3)-((x-2))=0

We multiply parentheses

20x-((x-2))+15=0



We calculate terms in parentheses: -((x-2)), so:

(x-2)

We get rid of parentheses

x-2

Back to the equation:

-(x-2)



We get rid of parentheses

20x-x+2+15=0

We add all the numbers together, and all the variables

19x+17=0

We move all terms containing x to the left, all other terms to the right

19x=-17

x=-17/19

x=-17/19

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