5(4x+32)=4(x+48)

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Solution for 5(4x+32)=4(x+48) equation: 



5(4x+32)=4(x+48)

We move all terms to the left:

5(4x+32)-(4(x+48))=0

We multiply parentheses

20x-(4(x+48))+160=0



We calculate terms in parentheses: -(4(x+48)), so:

4(x+48)

We multiply parentheses

4x+192

Back to the equation:

-(4x+192)



We get rid of parentheses

20x-4x-192+160=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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