5(4x+4)=-40+8x

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Solution for 5(4x+4)=-40+8x equation: 



5(4x+4)=-40+8x

We move all terms to the left:

5(4x+4)-(-40+8x)=0

We add all the numbers together, and all the variables

5(4x+4)-(8x-40)=0

We multiply parentheses

20x-(8x-40)+20=0

We get rid of parentheses

20x-8x+40+20=0

We add all the numbers together, and all the variables

12x+60=0

We move all terms containing x to the left, all other terms to the right

12x=-60

x=-60/12

x=-5

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