5(4x-1)+4(2x-1)=40

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Solution for 5(4x-1)+4(2x-1)=40 equation: 



5(4x-1)+4(2x-1)=40

We move all terms to the left:

5(4x-1)+4(2x-1)-(40)=0

We multiply parentheses

20x+8x-5-4-40=0

We add all the numbers together, and all the variables

28x-49=0

We move all terms containing x to the left, all other terms to the right

28x=49

x=49/28

x=1+3/4

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