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5(4x-1)=5(2x+1)
We move all terms to the left:
5(4x-1)-(5(2x+1))=0
We multiply parentheses
20x-(5(2x+1))-5=0
We calculate terms in parentheses: -(5(2x+1)), so:We get rid of parentheses
5(2x+1)
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
20x-10x-5-5=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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