5(4x-10)+10x=4(2x-3)+(2x-4)

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Solution for 5(4x-10)+10x=4(2x-3)+(2x-4) equation: 



5(4x-10)+10x=4(2x-3)+(2x-4)

We move all terms to the left:

5(4x-10)+10x-(4(2x-3)+(2x-4))=0

We add all the numbers together, and all the variables

10x+5(4x-10)-(4(2x-3)+(2x-4))=0

We multiply parentheses

10x+20x-(4(2x-3)+(2x-4))-50=0



We calculate terms in parentheses: -(4(2x-3)+(2x-4)), so:

4(2x-3)+(2x-4)

We multiply parentheses

8x+(2x-4)-12

We get rid of parentheses

8x+2x-4-12

We add all the numbers together, and all the variables

10x-16

Back to the equation:

-(10x-16)



We add all the numbers together, and all the variables

30x-(10x-16)-50=0

We get rid of parentheses

30x-10x+16-50=0

We add all the numbers together, and all the variables

20x-34=0

We move all terms containing x to the left, all other terms to the right

20x=34

x=34/20

x=1+7/10

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