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5(4x-10)+10x=4(2x-3)+2(x-4
We move all terms to the left:
5(4x-10)+10x-(4(2x-3)+2(x-4)=0
We add all the numbers together, and all the variables
10x+5(4x-10)-(4(2x-3)+2(x-4)=0
We multiply parentheses
10x+20x-(4(2x-3)+2(x-4)-50=0
We add all the numbers together, and all the variables
30x-(4(2x-3)+2(x-4)-50=0
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