5(4x-10)+10x=4(2x-3)+2x-4

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Solution for 5(4x-10)+10x=4(2x-3)+2x-4 equation:



5(4x-10)+10x=4(2x-3)+2x-4
We move all terms to the left:
5(4x-10)+10x-(4(2x-3)+2x-4)=0
We add all the numbers together, and all the variables
10x+5(4x-10)-(4(2x-3)+2x-4)=0
We multiply parentheses
10x+20x-(4(2x-3)+2x-4)-50=0
We calculate terms in parentheses: -(4(2x-3)+2x-4), so:
4(2x-3)+2x-4
We add all the numbers together, and all the variables
2x+4(2x-3)-4
We multiply parentheses
2x+8x-12-4
We add all the numbers together, and all the variables
10x-16
Back to the equation:
-(10x-16)
We add all the numbers together, and all the variables
30x-(10x-16)-50=0
We get rid of parentheses
30x-10x+16-50=0
We add all the numbers together, and all the variables
20x-34=0
We move all terms containing x to the left, all other terms to the right
20x=34
x=34/20
x=1+7/10

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