5(4x-12)=20(x-3)

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Solution for 5(4x-12)=20(x-3) equation:


Simplifying
5(4x + -12) = 20(x + -3)

Reorder the terms:
5(-12 + 4x) = 20(x + -3)
(-12 * 5 + 4x * 5) = 20(x + -3)
(-60 + 20x) = 20(x + -3)

Reorder the terms:
-60 + 20x = 20(-3 + x)
-60 + 20x = (-3 * 20 + x * 20)
-60 + 20x = (-60 + 20x)

Add '60' to each side of the equation.
-60 + 60 + 20x = -60 + 60 + 20x

Combine like terms: -60 + 60 = 0
0 + 20x = -60 + 60 + 20x
20x = -60 + 60 + 20x

Combine like terms: -60 + 60 = 0
20x = 0 + 20x
20x = 20x

Add '-20x' to each side of the equation.
20x + -20x = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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