5(4x-2)+3(6-3x)=2(5x+4)-7

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Solution for 5(4x-2)+3(6-3x)=2(5x+4)-7 equation: 



5(4x-2)+3(6-3x)=2(5x+4)-7

We move all terms to the left:

5(4x-2)+3(6-3x)-(2(5x+4)-7)=0

We add all the numbers together, and all the variables

5(4x-2)+3(-3x+6)-(2(5x+4)-7)=0

We multiply parentheses

20x-9x-(2(5x+4)-7)-10+18=0



We calculate terms in parentheses: -(2(5x+4)-7), so:

2(5x+4)-7

We multiply parentheses

10x+8-7

We add all the numbers together, and all the variables

10x+1

Back to the equation:

-(10x+1)



We add all the numbers together, and all the variables

11x-(10x+1)+8=0

We get rid of parentheses

11x-10x-1+8=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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