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5(4x-3)(4x+5)=0
We multiply parentheses ..
5(+16x^2+20x-12x-15)=0
We multiply parentheses
80x^2+100x-60x-75=0
We add all the numbers together, and all the variables
80x^2+40x-75=0
a = 80; b = 40; c = -75;
Δ = b2-4ac
Δ = 402-4·80·(-75)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-160}{2*80}=\frac{-200}{160} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+160}{2*80}=\frac{120}{160} =3/4 $
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