5(4x-3)+7x-5+2(x-1)=19

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Solution for 5(4x-3)+7x-5+2(x-1)=19 equation:



5(4x-3)+7x-5+2(x-1)=19
We move all terms to the left:
5(4x-3)+7x-5+2(x-1)-(19)=0
We add all the numbers together, and all the variables
7x+5(4x-3)+2(x-1)-24=0
We multiply parentheses
7x+20x+2x-15-2-24=0
We add all the numbers together, and all the variables
29x-41=0
We move all terms containing x to the left, all other terms to the right
29x=41
x=41/29
x=1+12/29

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