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5(4x-3)-2(2x+1)=15
We move all terms to the left:
5(4x-3)-2(2x+1)-(15)=0
We multiply parentheses
20x-4x-15-2-15=0
We add all the numbers together, and all the variables
16x-32=0
We move all terms containing x to the left, all other terms to the right
16x=32
x=32/16
x=2
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