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5(4x-3)-5(3x-7)=2(2x+4)-7
We move all terms to the left:
5(4x-3)-5(3x-7)-(2(2x+4)-7)=0
We multiply parentheses
20x-15x-(2(2x+4)-7)-15+35=0
We calculate terms in parentheses: -(2(2x+4)-7), so:We add all the numbers together, and all the variables
2(2x+4)-7
We multiply parentheses
4x+8-7
We add all the numbers together, and all the variables
4x+1
Back to the equation:
-(4x+1)
5x-(4x+1)+20=0
We get rid of parentheses
5x-4x-1+20=0
We add all the numbers together, and all the variables
x+19=0
We move all terms containing x to the left, all other terms to the right
x=-19
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