5(4x-5)+4(3x-4)=23

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Solution for 5(4x-5)+4(3x-4)=23 equation: 



5(4x-5)+4(3x-4)=23

We move all terms to the left:

5(4x-5)+4(3x-4)-(23)=0

We multiply parentheses

20x+12x-25-16-23=0

We add all the numbers together, and all the variables

32x-64=0

We move all terms containing x to the left, all other terms to the right

32x=64

x=64/32

x=2

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