5(4x-5)-23=-4(3x-4)

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Solution for 5(4x-5)-23=-4(3x-4) equation: 



5(4x-5)-23=-4(3x-4)

We move all terms to the left:

5(4x-5)-23-(-4(3x-4))=0

We multiply parentheses

20x-(-4(3x-4))-25-23=0



We calculate terms in parentheses: -(-4(3x-4)), so:

-4(3x-4)

We multiply parentheses

-12x+16

Back to the equation:

-(-12x+16)



We add all the numbers together, and all the variables

20x-(-12x+16)-48=0

We get rid of parentheses

20x+12x-16-48=0

We add all the numbers together, and all the variables

32x-64=0

We move all terms containing x to the left, all other terms to the right

32x=64

x=64/32

x=2

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