5(4x-7)-26=15(x-5)+34

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Solution for 5(4x-7)-26=15(x-5)+34 equation:



5(4x-7)-26=15(x-5)+34
We move all terms to the left:
5(4x-7)-26-(15(x-5)+34)=0
We multiply parentheses
20x-(15(x-5)+34)-35-26=0
We calculate terms in parentheses: -(15(x-5)+34), so:
15(x-5)+34
We multiply parentheses
15x-75+34
We add all the numbers together, and all the variables
15x-41
Back to the equation:
-(15x-41)
We add all the numbers together, and all the variables
20x-(15x-41)-61=0
We get rid of parentheses
20x-15x+41-61=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4

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