5(4x-7)-5=5(x-3)+80

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Solution for 5(4x-7)-5=5(x-3)+80 equation: 



5(4x-7)-5=5(x-3)+80

We move all terms to the left:

5(4x-7)-5-(5(x-3)+80)=0

We multiply parentheses

20x-(5(x-3)+80)-35-5=0



We calculate terms in parentheses: -(5(x-3)+80), so:

5(x-3)+80

We multiply parentheses

5x-15+80

We add all the numbers together, and all the variables

5x+65

Back to the equation:

-(5x+65)



We add all the numbers together, and all the variables

20x-(5x+65)-40=0

We get rid of parentheses

20x-5x-65-40=0

We add all the numbers together, and all the variables

15x-105=0

We move all terms containing x to the left, all other terms to the right

15x=105

x=105/15

x=7

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