5(4x-8)-4=5(x-4)+51

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Solution for 5(4x-8)-4=5(x-4)+51 equation:



5(4x-8)-4=5(x-4)+51
We move all terms to the left:
5(4x-8)-4-(5(x-4)+51)=0
We multiply parentheses
20x-(5(x-4)+51)-40-4=0
We calculate terms in parentheses: -(5(x-4)+51), so:
5(x-4)+51
We multiply parentheses
5x-20+51
We add all the numbers together, and all the variables
5x+31
Back to the equation:
-(5x+31)
We add all the numbers together, and all the variables
20x-(5x+31)-44=0
We get rid of parentheses
20x-5x-31-44=0
We add all the numbers together, and all the variables
15x-75=0
We move all terms containing x to the left, all other terms to the right
15x=75
x=75/15
x=5

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