5(4x-8)=20(x-2)

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Solution for 5(4x-8)=20(x-2) equation:


Simplifying
5(4x + -8) = 20(x + -2)

Reorder the terms:
5(-8 + 4x) = 20(x + -2)
(-8 * 5 + 4x * 5) = 20(x + -2)
(-40 + 20x) = 20(x + -2)

Reorder the terms:
-40 + 20x = 20(-2 + x)
-40 + 20x = (-2 * 20 + x * 20)
-40 + 20x = (-40 + 20x)

Add '40' to each side of the equation.
-40 + 40 + 20x = -40 + 40 + 20x

Combine like terms: -40 + 40 = 0
0 + 20x = -40 + 40 + 20x
20x = -40 + 40 + 20x

Combine like terms: -40 + 40 = 0
20x = 0 + 20x
20x = 20x

Add '-20x' to each side of the equation.
20x + -20x = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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