5(4y+2)=2(10y+5)

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Solution for 5(4y+2)=2(10y+5) equation: 



5(4y+2)=2(10y+5)

We move all terms to the left:

5(4y+2)-(2(10y+5))=0

We multiply parentheses

20y-(2(10y+5))+10=0



We calculate terms in parentheses: -(2(10y+5)), so:

2(10y+5)

We multiply parentheses

20y+10

Back to the equation:

-(20y+10)



We get rid of parentheses

20y-20y-10+10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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