5(4y+2)=2(2y-4)

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Solution for 5(4y+2)=2(2y-4) equation: 



5(4y+2)=2(2y-4)

We move all terms to the left:

5(4y+2)-(2(2y-4))=0

We multiply parentheses

20y-(2(2y-4))+10=0



We calculate terms in parentheses: -(2(2y-4)), so:

2(2y-4)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

20y-4y+8+10=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8

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