5(4y+2)=6(2y-8)-4y

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Solution for 5(4y+2)=6(2y-8)-4y equation: 



5(4y+2)=6(2y-8)-4y

We move all terms to the left:

5(4y+2)-(6(2y-8)-4y)=0

We multiply parentheses

20y-(6(2y-8)-4y)+10=0



We calculate terms in parentheses: -(6(2y-8)-4y), so:

6(2y-8)-4y

We add all the numbers together, and all the variables

-4y+6(2y-8)

We multiply parentheses

-4y+12y-48

We add all the numbers together, and all the variables

8y-48

Back to the equation:

-(8y-48)



We get rid of parentheses

20y-8y+48+10=0

We add all the numbers together, and all the variables

12y+58=0

We move all terms containing y to the left, all other terms to the right

12y=-58

y=-58/12

y=-4+5/6

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