5(4y+2)=80

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Solution for 5(4y+2)=80 equation: 



5(4y+2)=80

We move all terms to the left:

5(4y+2)-(80)=0

We multiply parentheses

20y+10-80=0

We add all the numbers together, and all the variables

20y-70=0

We move all terms containing y to the left, all other terms to the right

20y=70

y=70/20

y=3+1/2

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