5(4y+3)+3(4y+1)=66

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Solution for 5(4y+3)+3(4y+1)=66 equation:


Simplifying
5(4y + 3) + 3(4y + 1) = 66

Reorder the terms:
5(3 + 4y) + 3(4y + 1) = 66
(3 * 5 + 4y * 5) + 3(4y + 1) = 66
(15 + 20y) + 3(4y + 1) = 66

Reorder the terms:
15 + 20y + 3(1 + 4y) = 66
15 + 20y + (1 * 3 + 4y * 3) = 66
15 + 20y + (3 + 12y) = 66

Reorder the terms:
15 + 3 + 20y + 12y = 66

Combine like terms: 15 + 3 = 18
18 + 20y + 12y = 66

Combine like terms: 20y + 12y = 32y
18 + 32y = 66

Solving
18 + 32y = 66

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 32y = 66 + -18

Combine like terms: 18 + -18 = 0
0 + 32y = 66 + -18
32y = 66 + -18

Combine like terms: 66 + -18 = 48
32y = 48

Divide each side by '32'.
y = 1.5

Simplifying
y = 1.5

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