5(4y-3)=(9+6y)+46

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Solution for 5(4y-3)=(9+6y)+46 equation: 



5(4y-3)=(9+6y)+46

We move all terms to the left:

5(4y-3)-((9+6y)+46)=0

We add all the numbers together, and all the variables

5(4y-3)-((6y+9)+46)=0

We multiply parentheses

20y-((6y+9)+46)-15=0



We calculate terms in parentheses: -((6y+9)+46), so:

(6y+9)+46

We get rid of parentheses

6y+9+46

We add all the numbers together, and all the variables

6y+55

Back to the equation:

-(6y+55)



We get rid of parentheses

20y-6y-55-15=0

We add all the numbers together, and all the variables

14y-70=0

We move all terms containing y to the left, all other terms to the right

14y=70

y=70/14

y=5

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