5(4z+1)-6=179

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Solution for 5(4z+1)-6=179 equation: 



5(4z+1)-6=179

We move all terms to the left:

5(4z+1)-6-(179)=0

We add all the numbers together, and all the variables

5(4z+1)-185=0

We multiply parentheses

20z+5-185=0

We add all the numbers together, and all the variables

20z-180=0

We move all terms containing z to the left, all other terms to the right

20z=180

z=180/20

z=9

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