5(4z+1)-6=99

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Solution for 5(4z+1)-6=99 equation: 



5(4z+1)-6=99

We move all terms to the left:

5(4z+1)-6-(99)=0

We add all the numbers together, and all the variables

5(4z+1)-105=0

We multiply parentheses

20z+5-105=0

We add all the numbers together, and all the variables

20z-100=0

We move all terms containing z to the left, all other terms to the right

20z=100

z=100/20

z=5

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