5(4z-1)-2(z+1)=(z+1)

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Solution for 5(4z-1)-2(z+1)=(z+1) equation:


Simplifying
5(4z + -1) + -2(z + 1) = (z + 1)

Reorder the terms:
5(-1 + 4z) + -2(z + 1) = (z + 1)
(-1 * 5 + 4z * 5) + -2(z + 1) = (z + 1)
(-5 + 20z) + -2(z + 1) = (z + 1)

Reorder the terms:
-5 + 20z + -2(1 + z) = (z + 1)
-5 + 20z + (1 * -2 + z * -2) = (z + 1)
-5 + 20z + (-2 + -2z) = (z + 1)

Reorder the terms:
-5 + -2 + 20z + -2z = (z + 1)

Combine like terms: -5 + -2 = -7
-7 + 20z + -2z = (z + 1)

Combine like terms: 20z + -2z = 18z
-7 + 18z = (z + 1)

Reorder the terms:
-7 + 18z = (1 + z)

Remove parenthesis around (1 + z)
-7 + 18z = 1 + z

Solving
-7 + 18z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-7 + 18z + -1z = 1 + z + -1z

Combine like terms: 18z + -1z = 17z
-7 + 17z = 1 + z + -1z

Combine like terms: z + -1z = 0
-7 + 17z = 1 + 0
-7 + 17z = 1

Add '7' to each side of the equation.
-7 + 7 + 17z = 1 + 7

Combine like terms: -7 + 7 = 0
0 + 17z = 1 + 7
17z = 1 + 7

Combine like terms: 1 + 7 = 8
17z = 8

Divide each side by '17'.
z = 0.4705882353

Simplifying
z = 0.4705882353

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