5(4z-1)-2(z+1)=4(z+1)

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Solution for 5(4z-1)-2(z+1)=4(z+1) equation: 



5(4z-1)-2(z+1)=4(z+1)

We move all terms to the left:

5(4z-1)-2(z+1)-(4(z+1))=0

We multiply parentheses

20z-2z-(4(z+1))-5-2=0



We calculate terms in parentheses: -(4(z+1)), so:

4(z+1)

We multiply parentheses

4z+4

Back to the equation:

-(4z+4)



We add all the numbers together, and all the variables

18z-(4z+4)-7=0

We get rid of parentheses

18z-4z-4-7=0

We add all the numbers together, and all the variables

14z-11=0

We move all terms containing z to the left, all other terms to the right

14z=11

z=11/14

z=11/14

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