5(4z-1)-2(z+4)=12(z+1)

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Solution for 5(4z-1)-2(z+4)=12(z+1) equation:


Simplifying
5(4z + -1) + -2(z + 4) = 12(z + 1)

Reorder the terms:
5(-1 + 4z) + -2(z + 4) = 12(z + 1)
(-1 * 5 + 4z * 5) + -2(z + 4) = 12(z + 1)
(-5 + 20z) + -2(z + 4) = 12(z + 1)

Reorder the terms:
-5 + 20z + -2(4 + z) = 12(z + 1)
-5 + 20z + (4 * -2 + z * -2) = 12(z + 1)
-5 + 20z + (-8 + -2z) = 12(z + 1)

Reorder the terms:
-5 + -8 + 20z + -2z = 12(z + 1)

Combine like terms: -5 + -8 = -13
-13 + 20z + -2z = 12(z + 1)

Combine like terms: 20z + -2z = 18z
-13 + 18z = 12(z + 1)

Reorder the terms:
-13 + 18z = 12(1 + z)
-13 + 18z = (1 * 12 + z * 12)
-13 + 18z = (12 + 12z)

Solving
-13 + 18z = 12 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
-13 + 18z + -12z = 12 + 12z + -12z

Combine like terms: 18z + -12z = 6z
-13 + 6z = 12 + 12z + -12z

Combine like terms: 12z + -12z = 0
-13 + 6z = 12 + 0
-13 + 6z = 12

Add '13' to each side of the equation.
-13 + 13 + 6z = 12 + 13

Combine like terms: -13 + 13 = 0
0 + 6z = 12 + 13
6z = 12 + 13

Combine like terms: 12 + 13 = 25
6z = 25

Divide each side by '6'.
z = 4.166666667

Simplifying
z = 4.166666667

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