5(4z-1)-4(z+1)=14(z+1)

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Solution for 5(4z-1)-4(z+1)=14(z+1) equation:


Simplifying
5(4z + -1) + -4(z + 1) = 14(z + 1)

Reorder the terms:
5(-1 + 4z) + -4(z + 1) = 14(z + 1)
(-1 * 5 + 4z * 5) + -4(z + 1) = 14(z + 1)
(-5 + 20z) + -4(z + 1) = 14(z + 1)

Reorder the terms:
-5 + 20z + -4(1 + z) = 14(z + 1)
-5 + 20z + (1 * -4 + z * -4) = 14(z + 1)
-5 + 20z + (-4 + -4z) = 14(z + 1)

Reorder the terms:
-5 + -4 + 20z + -4z = 14(z + 1)

Combine like terms: -5 + -4 = -9
-9 + 20z + -4z = 14(z + 1)

Combine like terms: 20z + -4z = 16z
-9 + 16z = 14(z + 1)

Reorder the terms:
-9 + 16z = 14(1 + z)
-9 + 16z = (1 * 14 + z * 14)
-9 + 16z = (14 + 14z)

Solving
-9 + 16z = 14 + 14z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-14z' to each side of the equation.
-9 + 16z + -14z = 14 + 14z + -14z

Combine like terms: 16z + -14z = 2z
-9 + 2z = 14 + 14z + -14z

Combine like terms: 14z + -14z = 0
-9 + 2z = 14 + 0
-9 + 2z = 14

Add '9' to each side of the equation.
-9 + 9 + 2z = 14 + 9

Combine like terms: -9 + 9 = 0
0 + 2z = 14 + 9
2z = 14 + 9

Combine like terms: 14 + 9 = 23
2z = 23

Divide each side by '2'.
z = 11.5

Simplifying
z = 11.5

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