5(4z-1)-4(z+2)=13(z+1)

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Solution for 5(4z-1)-4(z+2)=13(z+1) equation:



5(4z-1)-4(z+2)=13(z+1)
We move all terms to the left:
5(4z-1)-4(z+2)-(13(z+1))=0
We multiply parentheses
20z-4z-(13(z+1))-5-8=0
We calculate terms in parentheses: -(13(z+1)), so:
13(z+1)
We multiply parentheses
13z+13
Back to the equation:
-(13z+13)
We add all the numbers together, and all the variables
16z-(13z+13)-13=0
We get rid of parentheses
16z-13z-13-13=0
We add all the numbers together, and all the variables
3z-26=0
We move all terms containing z to the left, all other terms to the right
3z=26
z=26/3
z=8+2/3

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