5(4z-1)-4(z+2)=13(z+1)

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Solution for 5(4z-1)-4(z+2)=13(z+1) equation: 



5(4z-1)-4(z+2)=13(z+1)

We move all terms to the left:

5(4z-1)-4(z+2)-(13(z+1))=0

We multiply parentheses

20z-4z-(13(z+1))-5-8=0



We calculate terms in parentheses: -(13(z+1)), so:

13(z+1)

We multiply parentheses

13z+13

Back to the equation:

-(13z+13)



We add all the numbers together, and all the variables

16z-(13z+13)-13=0

We get rid of parentheses

16z-13z-13-13=0

We add all the numbers together, and all the variables

3z-26=0

We move all terms containing z to the left, all other terms to the right

3z=26

z=26/3

z=8+2/3

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