5(4z-1)-4(z+4)=4(z+1)

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Solution for 5(4z-1)-4(z+4)=4(z+1) equation:


Simplifying
5(4z + -1) + -4(z + 4) = 4(z + 1)

Reorder the terms:
5(-1 + 4z) + -4(z + 4) = 4(z + 1)
(-1 * 5 + 4z * 5) + -4(z + 4) = 4(z + 1)
(-5 + 20z) + -4(z + 4) = 4(z + 1)

Reorder the terms:
-5 + 20z + -4(4 + z) = 4(z + 1)
-5 + 20z + (4 * -4 + z * -4) = 4(z + 1)
-5 + 20z + (-16 + -4z) = 4(z + 1)

Reorder the terms:
-5 + -16 + 20z + -4z = 4(z + 1)

Combine like terms: -5 + -16 = -21
-21 + 20z + -4z = 4(z + 1)

Combine like terms: 20z + -4z = 16z
-21 + 16z = 4(z + 1)

Reorder the terms:
-21 + 16z = 4(1 + z)
-21 + 16z = (1 * 4 + z * 4)
-21 + 16z = (4 + 4z)

Solving
-21 + 16z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-21 + 16z + -4z = 4 + 4z + -4z

Combine like terms: 16z + -4z = 12z
-21 + 12z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-21 + 12z = 4 + 0
-21 + 12z = 4

Add '21' to each side of the equation.
-21 + 21 + 12z = 4 + 21

Combine like terms: -21 + 21 = 0
0 + 12z = 4 + 21
12z = 4 + 21

Combine like terms: 4 + 21 = 25
12z = 25

Divide each side by '12'.
z = 2.083333333

Simplifying
z = 2.083333333

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