5(4z-1)-4(z+5)=12(z+1)

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Solution for 5(4z-1)-4(z+5)=12(z+1) equation:


Simplifying
5(4z + -1) + -4(z + 5) = 12(z + 1)

Reorder the terms:
5(-1 + 4z) + -4(z + 5) = 12(z + 1)
(-1 * 5 + 4z * 5) + -4(z + 5) = 12(z + 1)
(-5 + 20z) + -4(z + 5) = 12(z + 1)

Reorder the terms:
-5 + 20z + -4(5 + z) = 12(z + 1)
-5 + 20z + (5 * -4 + z * -4) = 12(z + 1)
-5 + 20z + (-20 + -4z) = 12(z + 1)

Reorder the terms:
-5 + -20 + 20z + -4z = 12(z + 1)

Combine like terms: -5 + -20 = -25
-25 + 20z + -4z = 12(z + 1)

Combine like terms: 20z + -4z = 16z
-25 + 16z = 12(z + 1)

Reorder the terms:
-25 + 16z = 12(1 + z)
-25 + 16z = (1 * 12 + z * 12)
-25 + 16z = (12 + 12z)

Solving
-25 + 16z = 12 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
-25 + 16z + -12z = 12 + 12z + -12z

Combine like terms: 16z + -12z = 4z
-25 + 4z = 12 + 12z + -12z

Combine like terms: 12z + -12z = 0
-25 + 4z = 12 + 0
-25 + 4z = 12

Add '25' to each side of the equation.
-25 + 25 + 4z = 12 + 25

Combine like terms: -25 + 25 = 0
0 + 4z = 12 + 25
4z = 12 + 25

Combine like terms: 12 + 25 = 37
4z = 37

Divide each side by '4'.
z = 9.25

Simplifying
z = 9.25

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