5(4z-6)-(z+3)=81

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Solution for 5(4z-6)-(z+3)=81 equation: 



5(4z-6)-(z+3)=81

We move all terms to the left:

5(4z-6)-(z+3)-(81)=0

We multiply parentheses

20z-(z+3)-30-81=0

We get rid of parentheses

20z-z-3-30-81=0

We add all the numbers together, and all the variables

19z-114=0

We move all terms containing z to the left, all other terms to the right

19z=114

z=114/19

z=6

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