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5(5+3x)+2x=6(2x+10)
We move all terms to the left:
5(5+3x)+2x-(6(2x+10))=0
We add all the numbers together, and all the variables
5(3x+5)+2x-(6(2x+10))=0
We add all the numbers together, and all the variables
2x+5(3x+5)-(6(2x+10))=0
We multiply parentheses
2x+15x-(6(2x+10))+25=0
We calculate terms in parentheses: -(6(2x+10)), so:We add all the numbers together, and all the variables
6(2x+10)
We multiply parentheses
12x+60
Back to the equation:
-(12x+60)
17x-(12x+60)+25=0
We get rid of parentheses
17x-12x-60+25=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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