5(5-2b)=3(1-4b)

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Solution for 5(5-2b)=3(1-4b) equation: 



5(5-2b)=3(1-4b)

We move all terms to the left:

5(5-2b)-(3(1-4b))=0

We add all the numbers together, and all the variables

5(-2b+5)-(3(-4b+1))=0

We multiply parentheses

-10b-(3(-4b+1))+25=0



We calculate terms in parentheses: -(3(-4b+1)), so:

3(-4b+1)

We multiply parentheses

-12b+3

Back to the equation:

-(-12b+3)



We get rid of parentheses

-10b+12b-3+25=0

We add all the numbers together, and all the variables

2b+22=0

We move all terms containing b to the left, all other terms to the right

2b=-22

b=-22/2

b=-11

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