5(5-a)=4(a-5)

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Solution for 5(5-a)=4(a-5) equation: 



5(5-a)=4(a-5)

We move all terms to the left:

5(5-a)-(4(a-5))=0

We add all the numbers together, and all the variables

5(-1a+5)-(4(a-5))=0

We multiply parentheses

-5a-(4(a-5))+25=0



We calculate terms in parentheses: -(4(a-5)), so:

4(a-5)

We multiply parentheses

4a-20

Back to the equation:

-(4a-20)



We get rid of parentheses

-5a-4a+20+25=0

We add all the numbers together, and all the variables

-9a+45=0

We move all terms containing a to the left, all other terms to the right

-9a=-45

a=-45/-9

a=+5

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