5(5-y)-37=25y-6(2+5y)

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Solution for 5(5-y)-37=25y-6(2+5y) equation: 



5(5-y)-37=25y-6(2+5y)

We move all terms to the left:

5(5-y)-37-(25y-6(2+5y))=0

We add all the numbers together, and all the variables

5(-1y+5)-(25y-6(5y+2))-37=0

We multiply parentheses

-5y-(25y-6(5y+2))+25-37=0



We calculate terms in parentheses: -(25y-6(5y+2)), so:

25y-6(5y+2)

We multiply parentheses

25y-30y-12

We add all the numbers together, and all the variables

-5y-12

Back to the equation:

-(-5y-12)



We add all the numbers together, and all the variables

-5y-(-5y-12)-12=0

We get rid of parentheses

-5y+5y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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