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5(5c+2)=5(3c+2)
We move all terms to the left:
5(5c+2)-(5(3c+2))=0
We multiply parentheses
25c-(5(3c+2))+10=0
We calculate terms in parentheses: -(5(3c+2)), so:We get rid of parentheses
5(3c+2)
We multiply parentheses
15c+10
Back to the equation:
-(15c+10)
25c-15c-10+10=0
We add all the numbers together, and all the variables
10c=0
c=0/10
c=0
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