5(5f-3)=5(4f-1)

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Solution for 5(5f-3)=5(4f-1) equation: 



5(5f-3)=5(4f-1)

We move all terms to the left:

5(5f-3)-(5(4f-1))=0

We multiply parentheses

25f-(5(4f-1))-15=0



We calculate terms in parentheses: -(5(4f-1)), so:

5(4f-1)

We multiply parentheses

20f-5

Back to the equation:

-(20f-5)



We get rid of parentheses

25f-20f+5-15=0

We add all the numbers together, and all the variables

5f-10=0

We move all terms containing f to the left, all other terms to the right

5f=10

f=10/5

f=2

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