5(5v+4)=5(6v-1)

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Solution for 5(5v+4)=5(6v-1) equation: 



5(5v+4)=5(6v-1)

We move all terms to the left:

5(5v+4)-(5(6v-1))=0

We multiply parentheses

25v-(5(6v-1))+20=0



We calculate terms in parentheses: -(5(6v-1)), so:

5(6v-1)

We multiply parentheses

30v-5

Back to the equation:

-(30v-5)



We get rid of parentheses

25v-30v+5+20=0

We add all the numbers together, and all the variables

-5v+25=0

We move all terms containing v to the left, all other terms to the right

-5v=-25

v=-25/-5

v=+5

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