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5(5v-1)=2(v+5)+8v
We move all terms to the left:
5(5v-1)-(2(v+5)+8v)=0
We multiply parentheses
25v-(2(v+5)+8v)-5=0
We calculate terms in parentheses: -(2(v+5)+8v), so:We get rid of parentheses
2(v+5)+8v
We add all the numbers together, and all the variables
8v+2(v+5)
We multiply parentheses
8v+2v+10
We add all the numbers together, and all the variables
10v+10
Back to the equation:
-(10v+10)
25v-10v-10-5=0
We add all the numbers together, and all the variables
15v-15=0
We move all terms containing v to the left, all other terms to the right
15v=15
v=15/15
v=1
| 7y=13y=-29-37- | | 67x=-37=-67=37 | | -50=6x+7x+2 | | 5x=9-3x=18+15 | | 2/3(x-6)+1=x-2 | | 7y=13y=-29-37 | | 3y^2/3=48 |